Materi : Garis Persamaan Lurus
Soal Nomor 26
2x + 3y - 1 = 0
3y = - 2x + 1
y = - ⅔x + ⅓ [ Gradien / m = -⅔ ]
\________________________/
Titik ( x¹ = 3 , y¹ = 2 ) dan m = -⅔
\____________/
y - y¹ = m( x - x¹ )
y - 2 = (-⅔)( x - 3 )
3( y - 2 ) = -2( x - 3 )
3y - 6 = - 2x + 6
3y + 2x = 0
Soal Nomor 27
x + 3y - 1 = 0
3y = - x + 1
y = - ⅓x + ⅓ [ Gradien / m = -⅓ ]
\________________________/
Titik ( x¹ = 3 , y¹ = 2 ) dan m = -⅓
\______________/
y - y¹ = ( -1/m )( x - x¹ )
y - 2 = ( -1/-⅓ )( x - 3 )
y - 2 = 3( x - 3 )
y - 2 = 3x - 9
y - 3x + 7 = 0
Semoga bisa membantu
[tex] \boxed{ \colorbox{navy}{ \sf{ \color{lightblue}{ Answer\:by\: BLUEBRAXGEOMETRY}}}} [/tex]
[answer.2.content]